Classical Statistical Mechanics
Phase space, Liouville's theorem, microstates and macrostates, statistical equilibrium, thermodynamic probability, density of states, and Stirling's approximation.
§1.1The Scope of Statistical Physics and Assemblies
1. Microscopic vs. Macroscopic Descriptions
In classical mechanics, the exact state of a system of $N$ particles is determined by specifying all generalized coordinates $q_i$ and conjugate momenta $p_i$ ($i = 1, 2, \dots, 3N$). In quantum mechanics, it is specified by an exact many-body state vector $|\Psi(t)\rangle$. This microscopic specification contains vastly more information than can ever be observed experimentally. Conversely, a **macroscopic description** characterizes the system using a few gross thermodynamic parameters: total internal energy $E$, volume $V$, pressure $P$, temperature $T$, and chemical potential $\mu$. Statistical mechanics demonstrates that macroscopic observables are exact statistical averages over accessible microscopic states: $$\langle A \rangle = \sum_{i} P_i A_i$$2. Definition of an Assembly and System Classifications
An **assembly** is a collection of a very large number $N$ of particles (atoms, molecules, ions, photons) confined within a macroscopic volume $V$. Assemblies are classified according to their boundary interactions with their surroundings:- Isolated Assembly: Exchanges neither energy nor matter with its surroundings. Constant internal energy $E$, volume $V$, and particle number $N$ ($dE = 0, dV = 0, dN = 0$).
- Closed Assembly: Exchanges energy (heat and mechanical work) with a surrounding thermal reservoir, but cannot exchange matter ($T, V, N$ fixed; $dN = 0$).
- Open Assembly: Exchanges both energy and matter with its surroundings ($T, V, \mu$ fixed).
3. The Role of Probability in Thermal Physics
Because macroscopic systems are in ceaseless microscopic motion, any macroscopic observable $M$ exhibits microscopic fluctuations $\Delta M$. For an assembly of $N$ particles, the central limit theorem dictates that relative fluctuations vanish as: $$\frac{\Delta M}{\langle M \rangle} \sim \frac{1}{\sqrt{N}} \sim \frac{1}{\sqrt{10^{23}}} = 10^{-11.5}$$ Thus, statistical averages predict macroscopic phenomena with virtually deterministic experimental precision.§1.2Phase Space and Phase Trajectories
1. Definition of Phase Space
For a system possessing $f$ degrees of freedom, its configuration is specified by $f$ generalized coordinates $q_1, q_2, \dots, q_f$, and its dynamical state requires $f$ generalized conjugate momenta $p_1, p_2, \dots, p_f$, where: $$p_i = \frac{\partial L}{\partial \dot{q}_i}$$ Phase space is an orthogonal, $2f$-dimensional Euclidean space whose Cartesian coordinate axes are $(q_1, \dots, q_f, p_1, \dots, p_f)$.2. $\mu$-Space versus $\Gamma$-Space
Following Paul and Tatyana Ehrenfest, we distinguish two fundamental phase space formalisms:- $\mu$-Space (Molecule Space): A 6-dimensional phase space $(x, y, z, p_x, p_y, p_z)$ for a single particle. An assembly of $N$ non-interacting particles is represented by a swarm of $N$ distinct points moving simultaneously in this 6D space.
- $\Gamma$-Space (Gas Phase Space): A $6N$-dimensional phase space for the entire assembly of $N$ particles. The instantaneous microstate of the entire macroscopic assembly corresponds to a single representative point: $$\mathbf{X} = (q_1, q_2, \dots, q_{3N}, p_1, p_2, \dots, p_{3N}) \in \mathbb{R}^{6N}$$ As time progresses, this single point traces out a continuous curve termed the phase trajectory.
3. Phase Trajectory of a 1D Harmonic Oscillator
Consider a 1D harmonic oscillator with mass $m$ and spring constant $k = m\omega^2$. The Hamiltonian is: $$H(q, p) = \frac{p^2}{2m} + \frac{1}{2}m\omega^2 q^2 = E$$ Rearranging in canonical ellipse form: $$\frac{q^2}{\left(\sqrt{\frac{2E}{m\omega^2}}\right)^2} + \frac{p^2}{\left(\sqrt{2mE}\right)^2} = 1$$ The phase trajectory is an ellipse centered at the origin with semi-axes: $$a = \sqrt{\frac{2E}{m\omega^2}}, \quad b = \sqrt{2mE}$$ The total area enclosed by this orbit in 2D phase space is: $$\oint p \, dq = \pi a b = \pi \sqrt{\frac{2E}{m\omega^2}} \sqrt{2mE} = \frac{2\pi E}{\omega} = \frac{E}{\nu}$$ This demonstrates that the phase trajectory for a conservative periodic system forms a closed loop whose enclosed phase volume is an adiabatic invariant.§1.3Volume in Phase Space and Specification of States
1. Differential Volume Element in Phase Space
The infinitesimal volume element $d\Gamma$ of $6N$-dimensional phase space is defined by: $$d\Gamma = dq_1 \, dq_2 \dots dq_{3N} \, dp_1 \, dp_2 \dots dp_{3N} = \prod_{i=1}^{3N} dq_i \, dp_i = d^{3N}q \, d^{3N}p$$ The dimensions of a coordinate times its conjugate momentum $[q_i p_i]$ are: $$[\text{length}] \times [\text{mass} \cdot \text{velocity}] = [\text{energy} \times \text{time}] = [\text{Action}] = \text{Joule} \cdot \text{second}$$ Therefore, each product $dq_i dp_i$ has physical dimensions of action ($\,\text{J}\cdot\text{s}$).2. Elementary Quantum Phase Cell Volume ($h_0$)
According to the Heisenberg uncertainty principle: $$\Delta q_i \Delta p_i \ge \frac{\hbar}{2} \sim h$$ Two physical microstates cannot be distinguished if they lie within a volume less than Planck's constant $h$. Thus, classical phase space is divided into discrete cells of volume: $$h_0 = h^{3N}$$ where $h = 6.626 \times 10^{-34}\text{ J}\cdot\text{s}$.3. Discrete Microstate Number
If an assembly occupies a finite accessible phase volume $\Delta \Gamma$, the number of quantum microstates $\Omega$ contained within this volume is: $$\Omega = \frac{\Delta \Gamma}{N! \, h^{3N}} = \frac{1}{N! \, h^{3N}} \int_{\Delta \Gamma} d^{3N}q \, d^{3N}p$$ The factor $N!$ accounts for Gibbs' correction for the fundamental indistinguishability of identical particles, preventing Gibbs' paradox in entropy calculations.§1.4Density of States and its General Behavior
1. Phase Volume Below Energy $E$
Let $\Phi(E)$ represent the total volume of phase space accessible to the system with total energy less than or equal to $E$: $$\Phi(E) = \int_{H(q, p) \le E} d^{3N}q \, d^{3N}p$$ The density of states $g(E)$ is the derivative of $\Phi(E)$ with respect to energy: $$g(E) = \frac{d\Phi(E)}{dE}$$ The number of microstates in a small energy shell $[E, E + \delta E]$ is: $$\Omega(E) = \frac{g(E) \, \delta E}{N! \, h^{3N}}$$2. Derivation for an Ideal Classical Gas of $N$ Particles
For an ideal gas of $N$ non-interacting particles of mass $m$ confined in a container of volume $V$, the Hamiltonian depends only on momenta: $$H = \sum_{i=1}^{3N} \frac{p_i^2}{2m} \le E$$ Integrating over all spatial coordinates yields: $$\int_V d^{3N}q = V^N$$ The momentum integral represents the volume of a $3N$-dimensional hypersphere of radius $R = \sqrt{2mE}$: $$\sum_{i=1}^{3N} p_i^2 \le 2mE$$ The volume of a $D$-dimensional hypersphere of radius $R$ is: $$V_D(R) = \frac{\pi^{D/2}}{\Gamma\left(\frac{D}{2} + 1\right)} R^D$$ Substituting $D = 3N$ and $R = (2mE)^{1/2}$: $$\Phi(E) = V^N \frac{\pi^{3N/2}}{\Gamma\left(\frac{3N}{2} + 1\right)} (2mE)^{3N/2}$$3. Exponential Growth with Particle Number
Differentiating with respect to $E$: $$g(E) = \frac{d\Phi}{dE} = V^N \frac{\pi^{3N/2}}{\Gamma\left(\frac{3N}{2}\right)} (2m)^{3N/2} E^{3N/2 - 1}$$ Because $N \sim 10^{23}$, the exponent $3N/2 - 1 \approx 10^{23}$. This shows that: $$g(E) \propto E^{10^{23}}$$ The density of states is an overwhelmingly, astronomically steep function of energy. Almost all states below energy $E$ are concentrated in an infinitesimally thin skin directly beneath $E$!§1.5Liouville's Theorem and its Dynamical Consequences
1. Ensemble Density in Phase Space
Consider an ensemble of $\mathcal{N}$ identical systems. Let $d\mathcal{N}$ be the number of representative points in phase volume $d\Gamma$ around point $(q, p)$ at time $t$. The phase-space probability density $\rho(q, p, t)$ is: $$\rho(q, p, t) = \lim_{\mathcal{N}\to\infty} \frac{d\mathcal{N}}{\mathcal{N} \, d\Gamma}$$ The total probability is normalized: $$\int \rho(q, p, t) \, d\Gamma = 1$$2. Continuity Equation in Phase Space
Because representative points cannot be created or destroyed (conservation of probability), $\rho$ satisfies the continuity equation in $2f$-dimensional phase space: $$\frac{\partial \rho}{\partial t} + \sum_{i=1}^{3N} \left[ \frac{\partial(\rho \dot{q}_i)}{\partial q_i} + \frac{\partial(\rho \dot{p}_i)}{\partial p_i} \right] = 0$$ Expanding the spatial derivatives: $$\frac{\partial \rho}{\partial t} + \sum_{i=1}^{3N} \left( \dot{q}_i \frac{\partial \rho}{\partial q_i} + \dot{p}_i \frac{\partial \rho}{\partial p_i} \right) + \rho \sum_{i=1}^{3N} \left( \frac{\partial \dot{q}_i}{\partial q_i} + \frac{\partial \dot{p}_i}{\partial p_i} \right) = 0$$3. Application of Hamilton's Canonical Equations
Hamilton's equations of motion state: $$\dot{q}_i = \frac{\partial H}{\partial p_i}, \quad \dot{p}_i = -\frac{\partial H}{\partial q_i}$$ Taking partial derivatives: $$\frac{\partial \dot{q}_i}{\partial q_i} = \frac{\partial^2 H}{\partial q_i \partial p_i}, \quad \frac{\partial \dot{p}_i}{\partial p_i} = -\frac{\partial^2 H}{\partial p_i \partial q_i}$$ Assuming $H$ is twice continuously differentiable, mixed partial derivatives commute: $$\frac{\partial \dot{q}_i}{\partial q_i} + \frac{\partial \dot{p}_i}{\partial p_i} = \frac{\partial^2 H}{\partial q_i \partial p_i} - \frac{\partial^2 H}{\partial p_i \partial q_i} = 0$$ The velocity field in phase space is strictly divergence-free: $\boldsymbol{\nabla}_{2f} \cdot \mathbf{v}_{\text{phase}} = 0$.4. The Liouville Equation and Incompressibility
The continuity equation reduces directly to: $$\frac{d\rho}{dt} = \frac{\partial \rho}{\partial t} + \sum_{i=1}^{3N} \left( \frac{\partial \rho}{\partial q_i} \dot{q}_i + \frac{\partial \rho}{\partial p_i} \dot{p}_i \right) = 0$$Liouville's Theorem: The convective (substantial) derivative of the phase space density following the motion of representative points is zero: $$\frac{d\rho}{dt} = 0$$ An ensemble of systems flows through phase space like an ideal, incompressible fluid.In terms of Poisson brackets, where $\{A, B\} = \sum_i \left( \frac{\partial A}{\partial q_i}\frac{\partial B}{\partial p_i} - \frac{\partial A}{\partial p_i}\frac{\partial B}{\partial q_i} \right)$: $$\frac{\partial \rho}{\partial t} = -\{\rho, H\}$$ For statistical equilibrium, $\frac{\partial \rho}{\partial t} = 0 \implies \{\rho, H\} = 0$. Hence, $\rho$ can only be a function of invariants of the motion (such as energy $H(q, p)$).
§1.6The Postulates of Classical Statistical Mechanics
1. The Postulate of Equal A Priori Probabilities
Fundamental Postulate: For an isolated system in thermodynamic equilibrium with energy $E$ in range $[E, E + \delta E]$, all accessible microscopic states within that energy shell are equally probable: $$P_i = \begin{cases} \frac{1}{\Omega(E)} & \text{if } E \le E_i \le E + \delta E \\ 0 & \text{otherwise} \end{cases}$$In phase space, this implies that the equilibrium density $\rho(q, p)$ is strictly uniform across the accessible energy hypersurface: $$\rho(q, p) = \begin{cases} C & \text{for } E \le H(q, p) \le E + \delta E \\ 0 & \text{elsewhere} \end{cases}$$
2. The Ergodic Hypothesis
How can an ensemble average (an imaginary average across $10^9$ parallel virtual universes) equal the time average observed by an experimenter measuring a single physical system over time? The **Ergodic Hypothesis** (Boltzmann, 1871) asserts:The phase trajectory of an isolated system passes through every single accessible point on the constant energy surface $H(q, p) = E$ before returning to its starting state.Because mathematical trajectories cannot intersect without self-repeating, modern physics relies on the **Quasi-Ergodic Theorem** (Birkhoff and von Neumann): The phase trajectory comes arbitrarily close to every accessible point on the energy surface and spends an amount of time in any phase region proportional to its phase volume: $$\langle A \rangle_{\text{time}} = \lim_{T\to\infty} \frac{1}{T} \int_0^T A(q(t), p(t)) \, dt = \int A(q, p) \rho(q, p) \, d\Gamma = \langle A \rangle_{\text{ensemble}}$$
§1.7Stirling's Approximation and Asymptotic Series
1. Integral Representation of $N!$
Using Euler's Gamma function: $$N! = \Gamma(N + 1) = \int_0^\infty x^N e^{-x} \, dx = \int_0^\infty e^{N \ln x - x} \, dx$$ Let $f(x) = N \ln x - x$. To evaluate this integral by the saddle-point (Laplace's) method, find the extremum of $f(x)$: $$f'(x) = \frac{N}{x} - 1 = 0 \implies x_0 = N$$ The second derivative at the peak is: $$f''(x_0) = -\frac{N}{x_0^2} = -\frac{1}{N} < 0$$ Expanding $f(x)$ in a Taylor series about $x_0 = N$: $$f(x) \approx f(N) + \frac{1}{2}f''(N)(x - N)^2 = N \ln N - N - \frac{(x - N)^2}{2N}$$2. Saddle-Point Gaussian Integration
Substitute this Taylor expansion into the integral: $$N! \approx e^{N \ln N - N} \int_{-\infty}^\infty e^{-\frac{(x - N)^2}{2N}} \, dx$$ Using the standard Gaussian integral $\int_{-\infty}^\infty e^{-u^2/(2N)} du = \sqrt{2\pi N}$: $$N! \approx \sqrt{2\pi N} \left(\frac{N}{e}\right)^N$$3. Logarithmic Form of Stirling's Approximation
Taking the natural logarithm of both sides: $$\ln(N!) = N \ln N - N + \frac{1}{2}\ln(2\pi N) + \mathcal{O}\left(\frac{1}{N}\right)$$ For macroscopic physics where $N \sim 10^{23}$: $$\frac{1}{2}\ln(2\pi N) \approx \frac{1}{2}\ln(10^{24}) \approx 27.6$$ While $N \ln N \sim 10^{23} \times 53 \sim 5.3 \times 10^{24}$. The logarithmic term $\frac{1}{2}\ln(2\pi N)$ is completely negligible compared to $N$: $$\ln(N!) \approx N \ln N - N$$ Differentiating with respect to $N$ yields the ubiquitous relation: $$\frac{d}{dN} \ln(N!) \approx \ln N$$§1.8Thermodynamic Probability and Statistical Weight
1. Mathematical Distinction: Mathematical Probability vs $W$
In ordinary mathematics, probability $P$ is a fraction between $0$ and $1$: $0 \le P \le 1$. In statistical physics, **thermodynamic probability** $W$ is an enormous integer ($W \ge 1$): $$W \in \{1, 2, 3, \dots, 10^{10^{23}}\}$$ The normalized mathematical probability of a macrostate is $P = W / \sum W$.2. Combinatorial Derivation for Two-Level Systems
Consider an assembly of $N$ localized, independent particles (such as magnetic spin-1/2 dipoles in an external magnetic field). Each particle can point UP ($+1$) or DOWN ($-1$). A macrostate is defined by the number of UP spins $n$ (leaving $N - n$ DOWN spins). The number of microscopic arrangements realizing this macrostate is given by the binomial coefficient: $$W(N, n) = \binom{N}{n} = \frac{N!}{n! \, (N - n)!}$$3. Determination of the Most Probable Macrostate
To find the macrostate that maximizes $W$, maximize $\ln W$ with respect to $n$: $$\ln W = \ln(N!) - \ln(n!) - \ln((N - n)!)$$ Applying Stirling's approximation $\ln(x!) \approx x \ln x - x$: $$\ln W \approx N\ln N - n\ln n - (N - n)\ln(N - n)$$ Setting the derivative to zero: $$\frac{\partial \ln W}{\partial n} = -\ln n - 1 + \ln(N - n) + 1 = \ln\left(\frac{N - n}{n}\right) = 0$$ $$\frac{N - n}{n} = 1 \implies n^* = \frac{N}{2}$$ The most probable macrostate occurs at exact symmetry: half the spins UP, half DOWN.4. Sharpness of the Multiplicity Peak
Expanding $\ln W(n)$ around $n^* = N/2 + \delta$: $$W(\delta) \approx W_{\max} \exp\left( -\frac{2\delta^2}{N} \right)$$ For $N = 10^{20}$, if the system deviates by just $\delta / N = 10^{-6}$ (one part in a million), the probability drops by: $$\exp\left( -2 \frac{(10^{14})^2}{10^{20}} \right) = \exp(-2 \times 10^8) \approx 10^{-86,858,896} \approx 0$$ The maximum macrostate is so overwhelmingly dominant that the system spends essentially $100\%$ of its time in this state.§1.9Statistical Equilibrium and the Boltzmann Entropy Relation
1. Thermal Contact Between Isolated Subsystems
Consider two isolated assemblies $A_1$ and $A_2$ with fixed volumes $V_1, V_2$ and particle numbers $N_1, N_2$. Let their energies be $E_1$ and $E_2$. Bring them into thermal contact through a rigid, impermeable, diathermal wall. The combined system $A = A_1 + A_2$ is isolated: $$E = E_1 + E_2 = \text{constant} \implies dE_1 = -dE_2$$ The total multiplicity of the composite system is the product of individual multiplicities: $$W(E, E_1) = W_1(E_1) \times W_2(E_2) = W_1(E_1) \times W_2(E - E_1)$$ Taking logarithms: $$\ln W(E, E_1) = \ln W_1(E_1) + \ln W_2(E_2)$$2. Condition for Statistical Equilibrium
In equilibrium, the combined system settles into the most probable energy configuration: $$\frac{\partial \ln W}{\partial E_1} = 0 \implies \frac{\partial \ln W_1}{\partial E_1} + \frac{\partial \ln W_2}{\partial E_2} \frac{\partial E_2}{\partial E_1} = 0$$ Since $\frac{\partial E_2}{\partial E_1} = -1$: $$\left(\frac{\partial \ln W_1}{\partial E_1}\right)_{V_1, N_1} = \left(\frac{\partial \ln W_2}{\partial E_2}\right)_{V_2, N_2}$$ We define the thermodynamic parameter $\beta$: $$\beta \equiv \left(\frac{\partial \ln W}{\partial E}\right)_{V, N}$$ Thermal equilibrium requires: $\beta_1 = \beta_2$.3. Derivation of the Boltzmann Entropy Relation ($S = k_B \ln W$)
In classical thermodynamics, thermal equilibrium between two bodies requires equality of temperature: $T_1 = T_2$. Furthermore, the thermodynamic definition of temperature is: $$\frac{1}{T} = \left(\frac{\partial S}{\partial E}\right)_{V, N}$$ Comparing this with $\beta = \frac{\partial \ln W}{\partial E}$, there must be a universal constant $k_B$ such that: $$\beta = \frac{1}{k_B T}$$ $$\frac{\partial S}{\partial E} = k_B \frac{\partial \ln W}{\partial E}$$ Integrating gives the celebrated **Boltzmann Entropy Formula**: $$S = k_B \ln W$$ where $k_B = 1.380649 \times 10^{-23}\text{ J/K}$ is Boltzmann's constant. Because $W_{12} = W_1 W_2$, the logarithm ensures that entropy is strictly additive: $$S_{12} = k_B \ln(W_1 W_2) = k_B \ln W_1 + k_B \ln W_2 = S_1 + S_2$$§1.10Macrostates and Microstates in Equilibrium Systems
1. Microscopic Chaos vs. Macroscopic Determinism
A **microstate** is a detailed microscopic snapshot: $$\mathbf{X}(t) = (q_1(t), \dots, q_{3N}(t), p_1(t), \dots, p_{3N}(t))$$ According to classical mechanics, microstates follow time-reversible Hamiltonian dynamics: if every particle velocity were reversed, the system would trace its path backward. Yet a **macrostate** is defined by thermodynamic variables $(E, V, N)$ and thermodynamic probability $W$. The Second Law of Thermodynamics states: $$dS \ge 0 \iff d\ln W \ge 0$$ Systems evolve spontaneously from macrostates of low multiplicity to macrostates of overwhelmingly high multiplicity.2. Why Systems Never Spontaneously De-mix
Consider $N = 10^{22}$ gas molecules initially confined to the left half of a container of volume $V$. The partition is removed. The probability that at any future time, all $N$ molecules will spontaneously be found simultaneously in the left half is: $$P = \left(\frac{1}{2}\right)^N = 2^{-10^{22}} = 10^{-3 \times 10^{21}}$$ Even if the universe existed for $10^{100}$ years, the probability of observing this fluctuation is effectively zero. Thermodynamic irreversibility is not a breakdown of microscopic mechanics; it is the statistical certainty of vast numbers!📝 Chapter Worked Examples & Exercises
Complete derivations & analytical proofsBecause the particle is free, the spatial integral is simply the container volume $V$, and the momentum integral is over a 3D sphere of radius $p_{\max} = E/c$.
This gives the total continuous volume of phase space occupied by states with energy up to $E$.
For an ultra-relativistic particle, the density of states scales quadratically with energy ($g(E) \propto E^2$), in contrast to the non-relativistic square root dependence ($g(E) \propto E^{1/2}$).
Here $\mathbf{p} = m\mathbf{v} + q\mathbf{A}$ is the canonical momentum, which differs from the mechanical momentum $m\mathbf{v}$.
These are the exact canonical velocity and force equations.
Summing over $i=1,2,3$ yields identically zero, proving that phase space volume is strictly conserved even in external electromagnetic fields.
Relate $n$ to energy: $E = -(2n - N)\mu B \implies n = \frac{N}{2} - \frac{E}{2\mu B}$, and $N - n = \frac{N}{2} + \frac{E}{2\mu B}$.
This gives the exact inverse temperature equation of state for the paramagnetic dipole system.
When energy $E > 0$, more than half the spins are inverted against the field ($n < N/2$). Adding energy inverts more spins toward the single state where all spins are antiparallel ($W=1$), so entropy decreases as energy increases ($dS/dE < 0$). This yields a physically genuine negative absolute temperature, hotter than $+\infty\text{ K}$.